Pressure versus temperature graph of an ideal gas is as shown in figure corresponding density (r) versus volume (V) graph will be –
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
B
Process AB is an isothermal process i.e. 
and since 
⇒ ρ -V graph will be rectangular
hyperbola. Pressure is increasing. Therefore volume will decrease and so density will increase. Process B-C is an isochoric process. Therefore V is constant and so r is also constant.
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