The time period of a particle executing SHM is T. Assume potential energy at mean position to be zero. After a time 
, it passes its mean position. Choose the incorrect option.
A
displacement will be half of its amplitude
B
velocity will be half of its maximum velocity
C
kinetic energy will be one-third of potential energy 1/3 (potential energy)
D
acceleration will be 
times of its maximum acceleration
times of its maximum acceleration
Text Solution
Verified by ExpertsThe correct answer is:
A
Let 
where 
At 
,
At 
,
K.E. 
.
and P.E. 
T.E. - K.E. 
T.E. 
K.E. 
(P.E.)
Acceleration 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
For a simple pendulum, the graph between and is a
In simple harmonic motion, the particle is
A simple harmonic oscillator has a period of 0.01 s and an amplitude of 0.2 m. The magnitude of the…
At a particular position, the velocity of a particle in SHM with amplitude a is times the velocity…
The particle is executing SHM on a 4 cm long line. If its velocity at mean position is , its frequ…
The velocity-time diagram of a harmonic oscillator is shown in the figure. The frequency of oscilla…