Maximum kinetic energy of a particle of mass 1 kg in SHM is 8 J. Time period of SHM is 4 s. Maximum potential energy during the motion is 10 J. Then,
A
amplitude of oscillations is approximately 4.53 m
B
minimum potential energy of the particle is 4 J
C
maximum acceleration of the particle is approximately 
D
minimum kinetic energy of the particle is 2 J
Text Solution
Verified by ExpertsThe correct answer is:
C
Maximum kinetic energy = Energy of oscillation in SHM
… (i)
… (ii)
From Eqs. (i) and (ii), we get
Maximum acceleration of the particle will be
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