A wave on a string passes the point x = 0 with amplitude A 0 , angular frequency ω ω 0 and average rate of energy transfer P 0 . As the wave travels down the string it gradually loses energy and at the point x = l the average rate of energy transfer becomes 
. At the point x = £angular frequency and amplitude are respectively:
Text Solution
Verified by ExpertsThe correct answer is:
A
P = 
A 2 v speed 
will not change as both T and µ are constant, ω ω will also not change as it is property of the source that is causing the wave motion. Hence to make power half, amplitude becomes A 0 /√2.
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