A copper rod of length l is rotated about one end, perpendicular to the uniform magnetic field B with constant angular velocity ω. The induced emf between two ends of the rod is:
Text Solution
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To calculate the emf we can imagine a closed loop by connecting the center with any point on the circumference, say X with a resistor.
Potential difference across the resistor is then equal to the induced emf. It arises due to separation of charges. 
(rate of change of area of loop)
If θ is the angle between the rod and 
the radius of circle at X at time t, the area of the arc formed by the rod and radius is
where, l is radius of the circle.
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