Charges +2q, +q and +q are placed at the corners A, B and C of an equilateral triangle ABC. If E is the electric field at the circumcenter O of the triangle, due to the charge +q, then the magnitude and direction of the resultant electric field at O is-
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The situation is as shown below. As shown we resolve E along CO and also along BO into two perpendicular components.
The horizontal components cancel each other. The vertical (cosine) components add up along OA to give 
.
Resultant field along 
Hence, resultant field is E along AO .
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