A charged particle ‘q’ is shot from a large distance with speed v towards a fixed charged particle Q. It approaches Q upto a closest distance r and then returns. If q were given a speed ‘2v’, the closest distance of approach would be:

Text Solution
Verified by ExpertsThe correct answer is:
D
Comparison can be shown as:
V → 2V
⇒ k → 4k
⇒ PE max → 4PE max
⇒ r → r/4
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