The below truth table corresponds to
0 | 0 | 1 |
1 | 0 | 1 |
0 | 1 | 1 |
1 | 1 | 0 |
Text Solution
Verified by ExpertsThe correct answer is:
A
Let's analyze the given truth table carefully:
A | B | Y |
0 | 0 | 1 |
1 | 0 | 1 |
0 | 1 | 1 |
1 | 1 | 0 |
We see that Y is 0 only when both A and B are 1. For all other input combinations, 
.
This is the NAND gate behavior because:
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
To obtain -type semiconductor, we need to dope pure Si with
If and represent the number of free electrons density and holes density respectively in a semicon…
An -type and -type silicon can be obtained by doping pure silicon with
Let and be the number of holes and conduction electrons respectively in a semiconductor, then
In -type semiconductor, the majority and minority charge carriers are respectively
The electrical resistance of which of the following decreases with rise in temperature?