In the circuit shown, the barrier voltage of diode is 0.7 V. Match the physical quantities given in Column I to the results given in Column II.

Column I | Column II | ||
(A) | Peak current (in mA) in diode | (I) | 37.8 |
(B) | Peak voltage (in volts) at the ends of load | (II) | 40.0 |
(C) | Peak current (in mA), if diode is ideal | (III) | 20.2 |
(D) | Peak voltage (in volts) at the ends of load, if diode is ideal | (IV) | 18.9 |
Choose the correct answer from the options given below.
Text Solution
Verified by ExpertsB
Diode gets forward biased during positive half cycle of alternating source and current flows. Let the barrier voltage of diode is
and its forward resistance be
and load resistance be
, then peak voltage of applied signal,



Peak voltage at the ends of the load
,

For ideal diode,
and 

and 
Hence, A-(I), B-(IV), C-(II), D-(III).
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