Arrange the following events of translation in the correct sequence:
A
Encounter of the release factor
B
Aminoacylation of tRNA
C
Attachment of the large ribosomal subunit
D
Encounter of the small ribosomal subunit with mRNA
(E) Formation of peptide bonds
(E) Formation of peptide bonds
Text Solution
Verified by ExpertsThe correct answer is:
A
First, tRNA molecules are charged with their respective amino acids (activation). The small subunit binds to mRNA and identifies the start codon. The large subunit joins to form a functional 80 S ribosome (in eukaryotes). Ribosome moves codon by codon, forming peptide bonds between amino acids (elongation). When a stop codon is reached, release factor binds, terminating translation.
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