A copper rod of length 'l' m is rotated about the end perpendicular to a uniform magnetic field of flux density 'B' with constant angular velocity 'ω'. The induced e.m.f. between the two ends is:
Text Solution
Verified by ExpertsThe correct answer is:
D
If in time 't', the rod turns by the angle 'θ', the area generated by the rotation of the rod will be:

So, the flux linked with the area generated by the rotation of the rod:

The induced EMF is:

Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
At a place, the value of horizontal component of the earth's magnetic field B H is . A metallic o…
A metallic frame moves with constant velocity v near a infinite-length current-carrying wire. At an…
A conducting of length is rotated about a point O in a uniform magnetic field , directed into th…
A rectangular coil has 60 turns and its length and width are 20 cm and 10 cm, respectively. The coi…
If the vertical component of earth's magnetic field is , then what will be the induced potential d…
A wire of length 4m, placed normal to the magnetic field of , is moving with a velocity . The emf…