Three inductances are connected as shown below. Assuming no coupling, the resultant inductance will be
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D
L 2 and L 3 are in parallel. Thus their combination gives 
The L ′ ′ and L 1 are in series, thus the equivalent inductance is L = L 1 + L ′ ′ = 0.75 + 0.25 = 1H.
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