Physics Electrostatics Potential & Capacitance Conductor, It's Properties & Electric Pressure Single Correct MCQ
Published on: September 11, 2026

The electric field near the conducting surface of a uniform charge density σ will be –

A
and parallel to surface.
B
and parallel to surface.
C
and perpendicular to surface.
D
and perpendicular to surface.

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Text Solution

Verified by Experts
The correct answer is:
C
To determine the electric field near a conducting surface with uniform charge density \( \sigma \), we can use Gauss's law. The electric field just outside a conducting surface is given by the formula: \[ E = \frac{\sigma}{\epsilon_0} \] where \( E \) is the electric field and \( \epsilon_0 \) is the permittivity of free space. This electric field is directed perpendicular to the surface of the conductor. Therefore, at the surface of the conductor, the electric field will be directed outwards and perpendicular to the surface.
Thus, the correct answer is option C: "and perpendicular to surface."

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