Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A certain elastic conducting material is stretched into a circular loop. It is placed with its plane perpendicular to a uniform magnetic field B = 0.8 T. When released the radius of the loop starts shrinking at a constant rate of 2 cm -1 . The induced emf in the loop at an instant when the radius of the loop is 10 cm will be ______mV.
Text Solution
Verified by ExpertsThe correct answer is:
10
(10)
EMF = 
= 2 
x 1.6 = 10.06 [round off 10.06 = 10]
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