A neutron travelling with a velocity v and K.E. E collides …

Physics Work, Energy, Power and Collision Energy Single Correct MCQ

Published on: September 11, 2026

A neutron travelling with a velocity v and K.E. E collides perfectly elastically head on with the nucleus of an atom of mass number A at rest. The fraction of total energy retained by neutron is

$\left(\frac{A-1}{A+1}\right)^2$

$\left(\frac{A+1}{A-1}\right)^2$

$\left(\frac{A-1}{A}\right)^2$

$\left(\frac{A+1}{A}\right)^2$

Text Solution

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The correct answer is:

$\left(\frac{\Delta k}{k}\right)_{\text{retained}} = \left(\frac{m_1 - m_2}{m_1 + m_2}\right)^2 = \left(\frac{1 - A}{1 + A}\right)^2$

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