Published by:
CGP EDU Academic Team
Published on: September 11, 2026
Figure shows ABCDEF as a regular hexagon. What is the value of \overrightarrow{AB} + \overrightarrow{AC} + \overrightarrow{AD} + \overrightarrow{AE} + \overrightarrow{AF}
A
\vec{A_0}
B
C
4 \vec{A}_0
D
6 \vec{A}_0
Text Solution
Verified by ExpertsThe correct answer is:
D
It is equal to 5\overrightarrow{AB} + 4\overrightarrow{BC} + 3\overrightarrow{CD} + 2\overrightarrow{DE} + \overrightarrow{EF} .
But \overrightarrow{AB} = - \overrightarrow{DE} and \overrightarrow{BC} = \overrightarrow{EF}
So, 3[\overrightarrow{AB} + \overrightarrow{BC} + \overrightarrow{CD}] = 3[\overrightarrow{AD}] = 6\overrightarrow{AO}
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