The length of second's hand in watch is 1 cm. The change in…

Physics Vectors Mix Single Correct MCQ

Published on: September 12, 2026

The length of second's hand in watch is 1 cm. The change in velocity of its tip in 15 seconds is

\((a) Zero (b) \frac{\pi}{30\sqrt{2}} \text{ cm/sec} (c) \frac{\pi}{30} \text{ cm/sec} (d) \frac{\pi \sqrt{2}}{30} \text{ cm/sec}\)

Text Solution

Verified by Experts

The correct answer is:

\(\Delta v = 2v \sin \left(\frac{90^\circ}{2}\right)\)

\(= 2v \sin 45^\circ = 2v \times \frac{1}{\sqrt{2}} = \sqrt{2} v\)

\(= \sqrt{2} \times r \omega = \sqrt{2} \times 1 \times \frac{2 \pi}{60}\)

\(= \frac{\sqrt{2 \pi}}{30} \text{ cm/s}\)

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