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CGP EDU Academic Team
Published on: September 11, 2026
If the acceleration due to gravity is \(10m\,s^{-2}\) and the units of length and time are changed in kilometer and hour respectively, the numerical value of the acceleration is
Text Solution
Verified by ExpertsThe correct answer is:
D
\(r_2 = r_1 \left| \begin{matrix} L_1 & \cdots & T_1 \\ L_2 & \cdots & T_2 \end{matrix} \right|^{-1}}\) \(=10 \left| \frac{\mathrm{meter}}{\mathrm{km}} \right|^{1} \left| \frac{\mathrm{sec}}{\mathrm{hr}} \right|^{-2}\)
\(n_2 \quad 10 \left| \frac{m}{10^3 m} \right|^1 \left| \frac{\sec}{3600 \sec^{-1}} \right|^2\) =129600
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