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CGP EDU Academic Team
Published on: September 12, 2026
A body starts from rest. What is the ratio of the distance travelled by the body during the 4th and 3rd second
Text Solution
Verified by ExpertsThe correct answer is:
A
\(S_n = u + \frac{\alpha}{2} (2n - 1) - \frac{\alpha}{2} (2n - 1)\) because \(\mathbf{v} = \mathbf{0}\)
Hence \(\frac{S_a}{S_s} = \frac{7}{5}\)
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