Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A very large number of balls are thrown vertically upwards in quick succession in such a way that the next ball is thrown when the previous one is at the maximum height. If the maximum height is 5 m , the number of ball thrown per minute is (take \(g = 10 \, m/s^{2}\) )
Text Solution
Verified by ExpertsThe correct answer is:
C
Maximum height of ball = 5 m
So velocity of projection \(\Rightarrow\) \(u = \sqrt{2gh}\) \(10 \text{ m/s}\)
Time interval between two balls (time of ascent)
\(= \frac{t}{g} = 1.5\,\text{sec} = \frac{1}{60}\,\text{min}\) .
So number of ball thrown per min. = 60
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