A rod is fixed between two points at 20°C. The coefficient …

Physics Elasticity ( Mechanical Properties of Solids ) Young’s Modulus and Breaking Stress Single Correct MCQ

Published on: September 12, 2026

A rod is fixed between two points at 20°C. The coefficient of linear expansion of material of rod is $1.1 \times 10^{-5} /^\circ C$ and Young's modulus is $1.2 \times 10^{11} \mathrm{N/m}$ . Find the stress developed in the rod if temperature of rod becomes 10°C

$1.32 \times 10^{7} \mathrm{N}/\mathrm{m}^{2}$

$1.10 \times 10^{15} \mathrm{N/m}^2$

$1.32 \times 10^{8} \mathrm{N}/\mathrm{m}^{2}$

$1.10 \times 10^{6} \mathrm{N}/\mathrm{m}^{2}$

Text Solution

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The correct answer is:

Thermal stress = ΥαΔθ

$= 1.2 \times 10^{11} \times 1.1 \times 10^{-5} \times (20 - 10) = 1.32 \times 10^{7} \text{ N/m}^2$

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