A copper wire and a steel wire of the same diameter and length are connected end to end and a force is applied, which stretches their combined length by 1 cm. The two wires will have
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$Stress = \frac{\text{Force}}{\text{area}}$ .
In the present case, force applied and area of cross-section of wires are same, therefore stress has to be the
same.
$\text{Strain} = \frac{\text{Stress}}{Y}$
Since the Young’s modulus of steel wire is greater than the copper wire, therefore, strain in case of steel
wire is less than that in case of copper wire.
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