A steel ring of radius r and cross-section area ‘A’ is fitted on to a wooden disc of radius 
. If Young's modulus be E, then the force with which the steel ring is expanded is
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
B
Initial length (circumference) of the ring = 2 π π r
Final length (circumference) of the ring = 2 π π R
Change in length = 2 π π R – 2 π π r.
Now Young's modulus 
∴ ∴ 
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