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CGP EDU Academic Team
Published on: September 12, 2026
The range of a particle when launched at an angle of 15^\circ with the horizontal is 1.5 km. What is the range of the projectile when launched at an angle of 45^\circ to the horizontal
Text Solution
Verified by ExpertsThe correct answer is:
B
\(R_{1.5} = \frac{-u^* g n (2 \times 15^3)}{\beta}\) \(-\frac{v^{2}}{2g} - 1.5\ \text{km}\)
\(R_{14} = - \frac{u^{2} \sin^{2} 2 \times 45^{\circ}}{g} - \frac{u^{2}}{g} - 1.5 \times 2 - 3\, \mathrm{km}\)
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