Home Physics Newton's Laws of Motion Second Law of Motion Two balls of masses m_{1} and m_{2} are sepa…
Physics Newton's Laws of Motion Second Law of Motion Single Correct MCQ
Published on: September 12, 2026

Two balls of masses m_{1} and m_{2} are separated from each other by a powder charge placed between them. The whole system is at rest on the ground. Suddenly the powder charge explodes and masses are pushed apart. The mass m_{1} travels a distance S_{1} and stops. If the coefficients of friction between the balls and ground are same, the mass m_{2} stops after travelling the distance

\((a) s_2 = \frac{m_1}{m_2} s_1 (b) s_2 = \frac{m_2}{m_1} s_1 (c) s_2 = \frac{m_1^2}{m_2^2} s_1 (d) s_2 = \frac{m_2^2}{m_1^2} s_1\)

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Text Solution

Verified by Experts
The correct answer is:
C

We know that in the given condition \(S \propto \frac{1}{m}\)

\(\cdot\) \(\frac{s_1}{s_2} = \left(\frac{m_1}{m_2}\right)^2\) ⇒ ⇒ \(s_2 = \left(\frac{m_2}{m_1}\right)^2 \times s_1\)

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