A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m/sec comes to rest after 2 sec. If one wants to keep this body moving on the same surface with a velocity of 4 m/sec, the force required is
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\(u = \frac{4 \mathrm{m}}{\mathrm{s}}, v = 0, t = 2 \mathrm{sec}\)
\(\mathbf{v} = \mathbf{u} + at \Rightarrow 0 = 4 + 2a \Rightarrow a = -2 \, \mathrm{m/s^{2}}\)
\(\therefore \text{Retarding force} = ma = 2 \times 2 = 4 \text{ N}\)
This force opposes the motion. If the same amount of force is applied in forward direction, then the body will move with constant velocity.
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