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CGP EDU Academic Team
Published on: September 11, 2026
If a bullet of mass 5 gm moving with velocity 100 m /sec, penetrates the wooden block up to 6 cm. Then the average force imposed by the bullet on the block is
Text Solution
Verified by ExpertsThe correct answer is:
B
\(u = \frac{100\, m}{s}, v = 0, s = 0.06\, m \\ \text{Retardation} = a = \frac{u^2}{2s} = \frac{(100)^2}{2 \times 0.06} = \frac{1 \times 10^4}{12} \\ \therefore \text{Force} = ma = \frac{5 \times 10^{-3} \times 1 \times 10^4}{12} = \frac{50}{12} = 4.17\, \text{N}\)
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