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CGP EDU Academic Team
Published on: September 12, 2026
If time of flight of a projectile is 10 seconds. Range is 500 meters. The maximum height attained by it will be
Text Solution
Verified by ExpertsThe correct answer is:
A
\(\tau = \frac{2u \sin \nu}{g} = 10 \mathrm{sec} \quad \Rightarrow \quad u \sin \nu = 50 \mathrm{m/s}\)
\ \ \(H = \frac{u^{2} \sin^{2} \alpha}{2g} - \frac{(u \sin \alpha)^{2}}{2g} - \frac{50 \times 50}{2 \times 10} = 125 \ m\)
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