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CGP EDU Academic Team
Published on: September 12, 2026
A ball thrown by one player reaches the other in 2 sec . the maximum height attained by the ball above the point of projection will be about
Text Solution
Verified by ExpertsThe correct answer is:
C
\(\frac{2u \sin \theta}{g} = 2 \sec \theta\) ⇒ ⇒ u_{sim} = 10
\ \ \(H = \frac{u^2 gn^2}{2g} - \frac{100}{2g} - 5m\)
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