Time taken by an object falling from rest to cover the heig…

Physics Motion in a Straight Line Motion Under Gravity Single Correct MCQ

Published on: September 12, 2026

Time taken by an object falling from rest to cover the height of h_{1} and \(\mathrm{H}_2\) is respectively t_{1} and \Sigma_2 then the ratio of t_{1} to \Gamma_2 is

h_{1} : h_{2}

\(\sqrt{y_1} : \sqrt{y_2}\)

h_{1} : 2h_{2}

2 h ₁ : h ₂

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The correct answer is:

\(t = \sqrt{\frac{2h}{g}} , \quad t_1 = \sqrt{\frac{h}{g}}, \quad t_2 = \psi \sqrt{h_2}\)

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