A body thrown vertically upwards with an initial velocity 21 reaches maximum height in 6 seconds. The ratio of the distances travelled by the body in the first second and the seventh second is
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Time of ascent \(\frac{t}{g} = 6 \text{ sec} \; ; \; u = 60 \text{ m/s}\)
Distance in first second \(h_{r,r} - 60 - \frac{g}{2} (2 \times 1 - 1) - 55 m\)
Distance in seventh second will be equal to the distance in first second of vertical downward motion \(h_{x=1-\eta_1} = -\frac{g}{2} (2 \times 1 - 1) - 5 m\) ⇒ ⇒ $h_{\mathrm{inc}} / h_{\mathrm{seam}}$ =11:1
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