Published by:
CGP EDU Academic Team
Published on: September 12, 2026
In a vertical circle of radius r , at what point in its path a particle has tension equal to zero if it is just able to complete the vertical circle
Text Solution
Verified by ExpertsThe correct answer is:
A
To determine at what point the tension in the rope (or the force acting on the particle) equals zero while the particle completes a vertical circle, we must first understand the forces acting on the particle.
When the particle is at the highest point of the vertical circle, only the gravitational force and the centripetal force need to be considered. At this point, the gravitational force contributes to the centripetal force needed to keep the particle in circular motion.
In uniform circular motion, the net force acting towards the center must equal the required centripetal force. Thus, the equation of motion at the highest point can be expressed as:
$$T + mg = \frac{mv^2}{r}$$
To find the condition where tension equals zero, we set T=0 in the equation:
$$0 + mg = \frac{mv^2}{r}$$
This simplifies to:
$$mg = \frac{mv^2}{r}$$
Therefore, this leads to:
$$v^2 = rg$$
This is the minimum velocity required at the highest point for the particle to just complete the circular motion without the need for tension in the string/rope.
Hence, the particle has zero tension at the highest point when it just manages to complete the vertical circle.
Therefore, the answer is option A.
When the particle is at the highest point of the vertical circle, only the gravitational force and the centripetal force need to be considered. At this point, the gravitational force contributes to the centripetal force needed to keep the particle in circular motion.
- At the highest point, the forces acting on the particle are:
- Weight (mg) acting downwards.
- Tension (T) acting downwards
In uniform circular motion, the net force acting towards the center must equal the required centripetal force. Thus, the equation of motion at the highest point can be expressed as:
$$T + mg = \frac{mv^2}{r}$$
To find the condition where tension equals zero, we set T=0 in the equation:
$$0 + mg = \frac{mv^2}{r}$$
This simplifies to:
$$mg = \frac{mv^2}{r}$$
Therefore, this leads to:
$$v^2 = rg$$
This is the minimum velocity required at the highest point for the particle to just complete the circular motion without the need for tension in the string/rope.
Hence, the particle has zero tension at the highest point when it just manages to complete the vertical circle.
Therefore, the answer is option A.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
In a circus stuntman rides a motorbike in a circular track of radius R in the vertical plane. The m…
A block of mass m at the end of a string is whirled round in a vertical circle of radius R. The cri…
A sphere is suspended by a thread of length l. What minimum horizontal velocity has to be imparted …
A bottle of soda water is grasped by the neck and swing briskly in a vertical circle. Near which po…
A bucket tied at the end of a 1.6 m long string is whirled in a vertical circle with constant speed…
A wheel is subjected to uniform angular acceleration about its axis. Initially its angular velocity…