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CGP EDU Academic Team
Published on: September 12, 2026
A body of mass \(\pi\) hangs at one end of a string of length l , the other end of which is fixed. It is given a horizontal velocity so that the string would just reach where it makes an angle of 60^{\circ} with the vertical. The tension in the string at mean position is
Text Solution
Verified by ExpertsThe correct answer is:
A
When body is released from the position p (inclined at angle q from vertical) then velocity at mean position
\(v = \sqrt{2g(1 - \cos r)}\)
\ \ Tension at the lowest point = \(mg + \frac{mv^2}{r}\)
\(-mg + \frac{m}{l} [2gl(1 - \cos 60)]\) = mg + mg = 2mg
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