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CGP EDU Academic Team
Published on: September 12, 2026
A stone is projected from the ground with velocity 25 m/s . Two seconds later, it just clears a wall 5 m high. The angle of projection of the stone is \(g = 10 \mathrm{m} / \mathrm{sec}^2\)
Text Solution
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A
For vertical upward motion \(\hbar - i \hat{\alpha} - \frac{i}{2} g \pi^{i}\)
\(5 - (25 \sin(\theta) / 2) - \frac{1}{2} \times 10 \times (2)^2\)
⇒ ⇒ 25 = 50 sin q ⇒ ⇒ \(3n/0 = -\frac{1}{2}\) ⇒ ⇒ \(\theta = 30^\circ\)
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