The equation of motion of a projectile are given by x = 36 t metre and 2 y = 96 t – 9.8 t 2 metre . The angle of projection is

The equation of motion of a projectile are given by x = 36 …

Physics Motion in a Plane Oblique Projectile Motion Single Correct MCQ

Published on: September 12, 2026

The equation of motion of a projectile are given by x = 36 t metre and 2 y = 96 t – 9.8 t ² metre . The angle of projection is

\(gn^{-11} \frac{4}{5}\)

\(gn^{-11} \frac{3i}{5}\)

\(\mathrm{gn}^{-1} : \frac{4}{3} :\)

\(\sin^{-1} \frac{3}{4}\)

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The correct answer is:

x = 36f \ \ \(v_x = -\frac{dx}{dt} = -36 \text{ m/s}\)

y = 48t - 4.9t^{2} \ \ v_y = 48 - 9.8t

at \ell = 0 \(\nu_s \quad 36\) and \(v_y \quad 48\ \mathrm{m/s}\)

So, angle of projection \(v = \tan^{-1} \left| \frac{v_y}{v_x} \right| = \tan^{-1} \left| \frac{4}{3} \right|\)

Or \(r = \sin^{-1}\left(\frac{4}{5}\right)\)

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