For a given velocity, a projectile has the same range R for two angles of projection if t 1 and t 2 are the times of flight in the two cases then

For a given velocity, a projectile has the same range R for…

Physics Motion in a Plane Oblique Projectile Motion Single Correct MCQ

Published on: September 12, 2026

For a given velocity, a projectile has the same range R for two angles of projection if t ₁ and t ₂ are the times of flight in the two cases then

\(t_1 t_2 \; r R^2\)

\(\zeta_1 \zeta_2 \times R\)

\(t_1 t_2 , \frac{1}{R}\)

\(\tau_1 t_2 \propto \frac{1}{R^2}\)

Text Solution

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The correct answer is:

For same range angle of projection should be q  and 90– q 

So, time of flights \(\ell = \frac{2v \sin \theta}{g}\) and

\(t_2 = \frac{2u \sin \beta_0}{g} = \frac{2u \cos r}{g}\)

By multiplying \(= t t_{2} = \frac{4 u^{2} r^{2} \sin \theta \cos \theta}{g^{2}}\)

\(\varepsilon_{t_s} = \frac{2 \left( u^o \sin 2u \right)}{g} - \frac{2R}{g}\) ⇒ ⇒ \(\Sigma_{12} \times \mathbb{R}\)

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