A particle of mass \(\left[ f \right]\) is moving in a circular path of constant radius f^{-} such that its centripetal acceleration a_c is varying with time t as, a_r = k^2 r^2 t^2 , The power delivered to the particle by the forces acting on it is
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Here the tangential acceleration also exits which requires power.
Given that a_c = k^2 r t and \(O_2 = -\frac{\nu^-}{r}\) \ \ \(\frac{v^2}{r} - k^2 n^2 =\)
or \(v^{2} \quad k^{2} r^{2} l^{2}\) or \(\mathbf{v} = k \mathbf{r}\)
Tangential acceleration \(\sigma - \frac{d\nu}{dt} = kr\)
Now force \(\mathbf{f} = n \times \sigma = n \pi d^2\)
So power \(\rho \quad E > v \quad n \dot{k} r \quad - k r \quad n \dot{k} \div r^{2} t\)
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