A particle \hat{p} is sliding down a frictionless hemispherical bowl. It passes the point A. at \{ = 0 . At this instant of time, the horizontal component of its velocity is v. A bead $\hat{q}$ of the same mass as \hat{p} is ejected from \hat{A} at \{ = 0 along the horizontal string \(A\beta\) (see figure) with the speed \vec{v} . Friction between the bead and the string may be neglected. Let t_p and \(\mathcal{E}_{c}\) be the respective time taken by \(\mathcal{P}\) and $\theta$ to reach the point \(\beta\) . Then

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For particle P , motion between A and C will be an accelerated one while between C and B a retarded one.
But in any case horizontal component of it’s velocity will be greater than or equal to v on the other hand in case of particle Q , it is always equal to v . horizontal displacement of both the particles are equal, so \tau_{p} < \tau_{0} .
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