The driver of a car travelling at velocity v suddenly see a broad wall in front of him at a distance d . He should
Text Solution
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When driver applies brakes and the car covers distance x before coming to rest, under the effect of
retarding force F
then \(\frac{1}{2} m v^{2} - F x\) ⇒ ⇒ \(x = \frac{r R V^{2}}{2F}\)
But when he takes turn then \(\frac{m v^{2}}{r} - F\) ⇒ ⇒ \(r - \frac{11N^{2}}{F}\)
It is clear that \(x \quad n 2\)
i.e. by the same retarding force the car can be stopped in a less distance if the driver apply breaks. This retarding force is actually a friction force.
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