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CGP EDU Academic Team
Published on: September 12, 2026
A stone falls from a balloon that is descending at a uniform rate of \(12 \ \mathrm{m/s}\) . The displacement of the stone from the point of release after 10 sec is
Text Solution
Verified by ExpertsThe correct answer is:
C
\(u = 12 \, m/s\) , g = 9.8 \ m / sec^{2} , \(t = 10 \text{ sec}\)
Displacement \(= ut + \frac{1}{2} gt^{2}\)
\(= 12 \times 10 + \frac{1}{2} \times 9.8 \times 100 = 610 \, m\)
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