A body of mass m hangs at one end of a string of length l , the other end of which is fixed. It is given a horizontal velocity so that the string would just reach where it makes an angle of 60^\circ with the vertical. The tension in the string at mean position is
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When body is released from the position p (inclined at angle θ θ from vertical) then velocity at mean position
\(v = \sqrt{2gl(1 - \cos \theta)}\)
∴ ∴ Tension at the lowest point = \(mg + \frac{mv^{2}}{l}\)
\(= mg + \frac{m}{l} \left[ \frac{2g}{1 - \cos 60} \right]\) = mg + mg = 2mg
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