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CGP EDU Academic Team
Published on: September 12, 2026
A tube of length \(\mathcal{L}\) is filled completely with an incompressible liquid of mass M and closed at both the ends. The tube is then rotated in a horizontal plane about one of its ends with a uniform angular velocity \(\alpha\) . The force exerted by the liquid at the other end is
Text Solution
Verified by ExpertsThe correct answer is:
A
\(dM = \left(\frac{M}{L}\right) dx\)

force on ‘ dM ’ mass is
\(dF = (dM) \omega^{2} x\)
By integration we can get the force exerted by whole liquid
⇒ ⇒ \(F = \int_0^L \frac{M}{L} \omega^2 x \, dx\) \(= \frac{1}{2} M \omega^{2} L\)
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