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CGP EDU Academic Team
Published on: September 12, 2026
A particle is moving eastwards with velocity of 5 m / s . In 10 sec the velocity changes to 5 m / s northwards. The average acceleration in this time is
Text Solution
Verified by ExpertsThe correct answer is:
B
\boxed{\Delta \nu} = \nu_{2} - \nu_{1} \(= \sqrt{v_1^2 + v_2^2 - 2 v_1 v_2 \cos 90^\circ}\) \(= \sqrt{5^{2} + 5^{2}} = 5 \sqrt{2}\)
Average acceleration
\(= \frac{\Delta v}{\Delta t} = \frac{5 \sqrt{2}}{10} = \frac{1}{\sqrt{2}} \text{ m/s}^2\)
Directed toward north-west
(As clear from the figure).
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