A bomb of 12 kg divides in two parts whose ratio of masses is 1 : 3. If kinetic energy of smaller part is 216 J, then momentum of bigger part in kg-m/sec will be
Text Solution
Verified by ExpertsThe correct answer is:
A
The bomb of mass 12kg divides into two masses
m 1 and m 2 then 
…(i)
and 
…(ii)
by solving we get 
and 
Kinetic energy of smaller part = 
∴ ∴ 
⇒ ⇒ 
So its momentum = 
As both parts possess same momentum therefore momentum of each part is 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Two bodies of masses and have equal kinetic energies. If and are their respective momentum, the…
Work done in raising a box depends on
A light and a heavy body have equal momenta. Which one has greater K.E
A body at rest may have
The kinetic energy possessed by a body of mass m moving with a velocity v is equal to , provided
If the momentum of a body is increased n times, its kinetic energy increases