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CGP EDU Academic Team
Published on: September 12, 2026
Given mass of the moon is 1/81 of the mass of the earth and corresponding radius is 1/4 of the earth. If escape velocity on the earth surface is 11.2 km/s, the value of same on the surface of the moon is
Text Solution
Verified by ExpertsThe correct answer is:
C
On earth $v_e = \sqrt{\frac{2GM}{R}} = 11.2 \text{ km/s}$
On moon $v_{m} = \sqrt{\frac{2GM \times 4}{81 \times R}} = \frac{2}{9} \sqrt{\frac{2GM}{R}}$
$= \frac{2}{9} \times 11.2 = 2.5 \text{ km/s}$
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