The velocity with which a projectile must be fired so that it escapes earth’s gravitation does not depend on
Text Solution
Verified by ExpertsThe correct answer is:
B
For a projectile to leave the gravitational field of the earth, its kinetic energy would be at least
equal to its potential energy.
That is 

where
is the universal gravitational constant,
is the mass of the earth and
is the radius of the earth.
Hence the escape velocity of a projectile is independent of its own mass.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A body of mass rises to height from the earth's surface, where R is earth's radius. If g is accel…
In a gravitational field, at a point where the gravitational potential is zero
The gravitational field due to a mass distribution is in the x-direction. (K is a constant). Takin…
The mass of the earth is and that of the moon is . The constant of gravitation . The potential e…
The change in potential energy, when a body of mass m is raised to a height nR from the earth's sur…
The masses and radii of the earth and moon are and respectively. Their centers are distance d apa…