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CGP EDU Academic Team
Published on: September 12, 2026
The escape velocity for the earth is $V_e$ . The escape velocity for a planet whose radius is four times and density is nine times that of the earth, is
Text Solution
Verified by ExpertsThe correct answer is:
B
$v \propto R \sqrt{\rho}$ ∴ ∴ $\frac{v_p}{v_e} = \frac{R_p}{R_e} \times \sqrt{\frac{\rho_p}{\rho_e}} = 4 \times \sqrt{9} = 12$
⇒ ⇒ $V_{p} = 12 V_{e}$
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