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CGP EDU Academic Team
Published on: September 12, 2026
If the radius of a planet is four times that of earth and the value of g is same for both, the escape velocity on the planet will be
Text Solution
Verified by ExpertsThe correct answer is:
C
$v = \sqrt{2gR}$ ⇒ ⇒ $\frac{v_p}{v_e} = \sqrt{\frac{g_p}{g_e} \times \frac{R_p}{R_e}} = \sqrt{1 \times 4} = 2$
⇒ ⇒ $v_{p} = 2 \times v_{e} = 2 \times 11.2 = 22.4 \, km/s$
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