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CGP EDU Academic Team
Published on: September 12, 2026
A planet has twice the radius but the mean density is $\frac{1}{4} + th$ as compared to earth. What is the ratio of escape velocity from earth to that from the planet
Text Solution
Verified by ExpertsThe correct answer is:
C
$\frac{v_{\rho_2}}{v_{\rho_1}} = \frac{R_2}{R_1} \sqrt{\frac{\rho_2}{\rho_1}} = 2 \times \sqrt{\frac{1}{4}} = 2 \times \frac{1}{2} = 1$
$\frac{v_{\rho_2}}{v_{\rho_1}} = \frac{1}{1}$
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