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CGP EDU Academic Team
Published on: September 12, 2026
Four particles each of mass M, are located at the vertices of a square with side L. The gravitational potential due to this at the centre of the square is
Text Solution
Verified by ExpertsThe correct answer is:
A
Potential at the centre due to single mass = $-\overline{GM}$ $\frac{L}{\nu \sqrt{2}}$
Potential at the center due to all four masses
= $-4 \frac{GM}{L \sqrt{2}}$ $-4 \sqrt{2} \frac{GM}{L}$
$= - \sqrt{32} \times \frac{GM}{L} .$
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